qemu/msix: fix table access issues

Fixes a couple of issues with msix table access:
- With misbehaving guests, misaligned 4 byte access could overflow
  msix table and cause qemu to segfault. Since PCI spec requires
  host to only issue dword-aligned accesses, as a fix,
  it's enough to mask the address low bits.
- Tables use pci format, not native format, and so
  we must use pci_[sg]et_long on read/write.

Reported-by: Juan Quintela <quintela@redhat.com>
Signed-off-by: Michael S. Tsirkin <mst@redhat.com>
Signed-off-by: Anthony Liguori <aliguori@us.ibm.com>

hw/msix.c

diff --git a/hw/msix.c b/hw/msix.c
index b0dea91..3d67c4e 100644
--- a/hw/msix.c
+++ b/hw/msix.c
@@ -128,13 +128,10 @@
 static uint32_t msix_mmio_readl(void *opaque, target_phys_addr_t addr)
 {
     PCIDevice *dev = opaque;
-    unsigned int offset = addr & (MSIX_PAGE_SIZE - 1);
+    unsigned int offset = addr & (MSIX_PAGE_SIZE - 1) & ~0x3;
     void *page = dev->msix_table_page;
-    uint32_t val = 0;
 
-    memcpy(&val, (void *)((char *)page + offset), 4);
-
-    return val;
+    return pci_get_long(page + offset);
 }
 
 static uint32_t msix_mmio_read_unallowed(void *opaque, target_phys_addr_t addr)
@@ -178,9 +175,9 @@
                              uint32_t val)
 {
     PCIDevice *dev = opaque;
-    unsigned int offset = addr & (MSIX_PAGE_SIZE - 1);
+    unsigned int offset = addr & (MSIX_PAGE_SIZE - 1) & ~0x3;
     int vector = offset / MSIX_ENTRY_SIZE;
-    memcpy(dev->msix_table_page + offset, &val, 4);
+    pci_set_long(dev->msix_table_page + offset, val);
     if (!msix_is_masked(dev, vector) && msix_is_pending(dev, vector)) {
         msix_clr_pending(dev, vector);
         msix_notify(dev, vector);